- The bond angle in water (H₂O) is approximately:
A. 109.5°
B. 107°
C. 104.5°
D. 90°
Answer: C. 104.5°
Explanation: In water (H₂O), the oxygen atom undergoes sp³ hybridization, and the bond angle is reduced to about 104.5° due to the lone pairs of electrons on oxygen.
- In VBT, delocalization of electrons is explained by:
A. Overlap of atomic orbitals
B. Resonance structures
C. Hybridization
D. Bond dissociation energy
Answer: B. Resonance structures
Explanation: Delocalization of electrons in VBT is often explained using resonance, where electrons are shared among multiple atoms across several valid Lewis structures.
- In benzene (C₆H₆), the hybridization of each carbon atom is:
A. sp
B. sp²
C. sp³
D. sp³d
Answer: B. sp²
Explanation: In benzene, each carbon atom is sp² hybridized, and the delocalized pi electrons form a conjugated ring system, giving the molecule its planar structure.
- The bond angle in a molecule of CO₂ is:
A. 90°
B. 104.5°
C. 120°
D. 180°
Answer: D. 180°
Explanation: In carbon dioxide (CO₂), the central carbon atom is sp hybridized, resulting in a linear structure with a bond angle of 180°.
- In VBT, the strength of a pi bond is:
A. Equal to that of a sigma bond
B. Greater than that of a sigma bond
C. Less than that of a sigma bond
D. Dependent on hybridization
Answer: C. Less than that of a sigma bond
Explanation: A pi bond is generally weaker than a sigma bond because it arises from the sideways overlap of p-orbitals, which is less effective than the head-on overlap that forms a sigma bond.
- The bond order of nitrogen (N₂) is:
A. 1
B. 2
C. 3
D. 4
Answer: C. 3
Explanation: In nitrogen (N₂), the bond order is 3, meaning the two nitrogen atoms are connected by a triple bond (one sigma and two pi bonds).
- Which of the following molecules has a tetrahedral structure?
A. NH₃
B. H₂O
C. CH₄
D. CO₂
Answer: C. CH₄
Explanation: Methane (CH₄) has a tetrahedral structure, as the carbon atom is sp³ hybridized, and the bond angles are 109.5°.
- In VBT, the bond angle in a molecule depends primarily on:
A. The number of pi bonds
B. The number of lone pairs
C. The hybridization of the central atom
D. The size of the atoms involved
Answer: C. The hybridization of the central atom
Explanation: The bond angle in a molecule is largely determined by the hybridization of the central atom, which dictates the spatial arrangement of the bonding orbitals.
- The hybridization of carbon in C₂H₂ is:
A. sp
B. sp²
C. sp³
D. sp³d
Answer: A. sp
Explanation: In acetylene (C₂H₂), each carbon atom is sp hybridized, resulting in a linear structure with bond angles of 180°.
- In VBT, the formation of a sigma bond is always due to:
A. Sideways overlap of orbitals
B. End-to-end overlap of orbitals
C. Overlap of d-orbitals
D. Overlap of pi orbitals
Answer: B. End-to-end overlap of orbitals
Explanation: A sigma bond is formed by the head-on (end-to-end) overlap of atomic orbitals, which results in stronger bonding than a pi bond.
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