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Home/ Chemistry/“Valence Bond Theory” MCQ with Answer Explanation : NEET 2025.

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On: October 5, 2024 Posted in Chemistry, Education, Exam, NEET Comments: 0 Views: 85

“Valence Bond Theory” MCQ with Answer Explanation : NEET 2025.

  1. Which of the following molecules exhibits sp hybridization?
    A. BeF₂
    B. NH₃
    C. BF₃
    D. H₂O

Answer: A. BeF₂

Explanation: In beryllium fluoride (BeF₂), beryllium is sp hybridized, resulting in a linear structure with bond angles of 180°.

  1. In SF₆, the sulfur atom undergoes:
    A. sp hybridization
    B. sp³ hybridization
    C. sp³d hybridization
    D. sp³d² hybridization

Answer: D. sp³d² hybridization

Explanation: In sulfur hexafluoride (SF₆), sulfur undergoes sp³d² hybridization, leading to an octahedral shape with bond angles of 90°.

  1. The hybridization of the central atom in PCl₅ is:
    A. sp³
    B. sp²
    C. sp³d
    D. sp³d²

Answer: C. sp³d

Explanation: In phosphorus pentachloride (PCl₅), phosphorus is sp³d hybridized, which results in a trigonal bipyramidal shape.

  1. The bond order in O₂ is:
    A. 1
    B. 2
    C. 2.5
    D. 3

Answer: B. 2

Explanation: In the oxygen molecule (O₂), the bond order is 2, indicating a double bond consisting of one sigma bond and one pi bond.

  1. Which of the following molecules has a trigonal pyramidal shape?
    A. BF₃
    B. NH₃
    C. H₂O
    D. CO₂

Answer: B. NH₃

Explanation: In ammonia (NH₃), nitrogen is sp³ hybridized, resulting in a trigonal pyramidal shape with a bond angle of about 107°.

  1. In VBT, the term bond dissociation energy refers to:
    A. The energy required to break a bond
    B. The energy released when a bond forms
    C. The energy associated with pi bonds only
    D. The energy required to form a hybrid orbital

Answer: A. The energy required to break a bond

Explanation: Bond dissociation energy is the energy required to break a chemical bond in a molecule, resulting in the formation of separate atoms.

  1. In a molecule of ethene (C₂H₄), the hybridization of each carbon atom is:
    A. sp
    B. sp²
    C. sp³
    D. sp³d

Answer: B. sp²

Explanation: In ethene (C₂H₄), each carbon atom is sp² hybridized, leading to a planar structure with one sigma bond and one pi bond between the carbons.

  1. The bond order in a triple bond is:
    A. 1
    B. 2
    C. 3
    D. 4

Answer: C. 3

Explanation: A triple bond has a bond order of 3, consisting of one sigma bond and two pi bonds.

  1. In VBT, the geometry of a molecule is primarily determined by:
    A. The number of sigma and pi bonds
    B. The hybridization of the central atom
    C. The total number of valence electrons
    D. The mass of the atoms

Answer: B. The hybridization of the central atom

Explanation: The geometry of a molecule is largely determined by the hybridization state of the central atom, which defines how the orbitals are arranged in space.

  1. Which of the following molecules involves sp³d² hybridization?
    A. PCl₅
    B. SF₆
    C. BF₃
    D. CH₄

Answer: B. SF₆

Explanation: In sulfur hexafluoride (SF₆), sulfur undergoes sp³d² hybridization, resulting in an octahedral structure with bond angles of 90°.

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