“Valence Bond Theory” MCQ with Answer Explanation : NEET 2025.

21. The shape of SF₆ can be explained using which type of hybridization?
    A. sp²
    B. sp³d²
    C. sp³d
    D. sp³

Answer: B. sp³d²

Explanation: In sulfur hexafluoride (SF₆), sulfur is sp³d² hybridized, leading to an octahedral geometry with 90° bond angles.

22. Which of the following molecules has no lone pair on its central atom?
    A. NH₃
    B. H₂O
    C. CH₄
    D. SO₂

Answer: C. CH₄

Explanation: In methane (CH₄), the carbon atom forms four sigma bonds and has no lone pairs. In contrast, NH₃ and H₂O have lone pairs on the central atom.

23. In the Valence Bond Theory, a pi bond forms due to:
    A. Head-to-head overlap of p-orbitals
    B. Side-to-side overlap of p-orbitals
    C. Overlap of s-orbitals
    D. Overlap of d-orbitals

Answer: B. Side-to-side overlap of p-orbitals

Explanation: A pi bond is formed by the lateral (side-to-side) overlap of unhybridized p-orbitals.

24. Which of the following statements is true about hybrid orbitals in VBT?
    A. Hybrid orbitals have the same energy as the original atomic orbitals.
    B. Hybrid orbitals are less directional than atomic orbitals.
    C. Hybrid orbitals result in maximum overlap and stronger bonds.
    D. Hybrid orbitals always form pi bonds.

Answer: C. Hybrid orbitals result in maximum overlap and stronger bonds.

Explanation: Hybridization allows for maximum overlap of orbitals, leading to stronger and more stable covalent bonds.

25. The bond angle in BeCl₂ is:
    A. 109.5°
    B. 120°
    C. 180°
    D. 90°

Answer: C. 180°

Explanation: In BeCl₂, the central beryllium atom is sp hybridized, giving the molecule a linear shape with a bond angle of 180°.

26. In sp² hybridization, the number of hybrid orbitals formed is:
    A. 2
    B. 3
    C. 4
    D. 5

Answer: B. 3

Explanation: In sp² hybridization, one s orbital and two p orbitals mix to form three sp² hybrid orbitals, which are arranged in a trigonal planar geometry.

27. The bond order of a molecule can be predicted by VBT when:
    A. Bonding and antibonding orbitals are equally occupied
    B. There is maximum overlap of orbitals
    C. Orbitals do not overlap
    D. Only hybrid orbitals are involved

Answer: B. There is maximum overlap of orbitals

Explanation: In VBT, a higher bond order is associated with greater overlap of atomic orbitals, leading to stronger bonds.

28. In PCl₃, the central phosphorus atom undergoes:
    A. sp³ hybridization
    B. sp hybridization
    C. sp² hybridization
    D. sp³d hybridization

Answer: A. sp³ hybridization

Explanation: In phosphorus trichloride (PCl₃), phosphorus undergoes sp³ hybridization, resulting in a trigonal pyramidal shape with one lone pair.

29. In SF₄, the shape of the molecule can be explained using:
    A. sp² hybridization
    B. sp³ hybridization
    C. sp³d hybridization
    D. sp³d² hybridization

Answer: C. sp³d hybridization

Explanation: In sulfur tetrafluoride (SF₄), sulfur undergoes sp³d hybridization, which leads to a seesaw-shaped molecular geometry.

30. How many pi bonds are present in a molecule of C₂H₂ (ethyne)?
    A. 0
    B. 1
    C. 2
    D. 3

Answer: C. 2

Explanation: In ethyne (C₂H₂), there is one sigma bond and two pi bonds between the two carbon atoms, forming a triple bond.