Here below some basic MCQ’s about “Trends in periodic properties” which is explained in details. Let’s check one by one which is given below.
- Which of the following elements has the highest first ionization energy?
a) Sodium (Na)
b) Magnesium (Mg)
c) Aluminum (Al)
d) Phosphorus (P)
Answer: d) Phosphorus (P)
Explanation: Ionization energy generally increases across a period due to the increasing effective nuclear charge, which makes it harder to remove an electron. Phosphorus lies farthest to the right in this group, hence has a higher ionization energy than Na, Mg, and Al. Also, due to half-filled p-orbital stability, phosphorus has a higher ionization energy than aluminum.
- Which of the following elements has the largest atomic radius?
a) Carbon (C)
b) Nitrogen (N)
c) Oxygen (O)
d) Fluorine (F)
Answer: a) Carbon (C)
Explanation: Atomic radius decreases across a period from left to right due to increasing effective nuclear charge. Carbon, being the leftmost element in this group, has the largest atomic radius among these elements.
- In which period of the periodic table is the element with the electronic configuration [Ar] 3d¹⁰ 4s² 4p⁵ located?
a) Period 3
b) Period 4
c) Period 5
d) Period 6
Answer: b) Period 4
Explanation: The element has the outer electronic configuration 4s² 4p⁵, indicating that the last electron enters the 4th energy level. This places the element in period 4. The element is bromine (Br).
- Which of the following oxides is most acidic?
a) Na₂O
b) Al₂O₃
c) SiO₂
d) SO₃
Answer: d) SO₃
Explanation: Acidity of oxides increases across a period and decreases down a group. Non-metal oxides (like SO₃) tend to be more acidic, while metal oxides (like Na₂O) are basic. SO₃, being a non-metal oxide, is highly acidic.
- Which property decreases down the group in alkali metals?
a) Atomic radius
b) Ionization energy
c) Metallic character
d) Electronegativity
Answer: d) Electronegativity
Explanation: As we move down the group in alkali metals, atomic size increases, leading to decreased attraction for electrons, hence decreasing electronegativity. Ionization energy also decreases, but metallic character increases down the group.
- Which of the following elements has the smallest electron affinity?
a) Fluorine (F)
b) Chlorine (Cl)
c) Oxygen (O)
d) Sulfur (S)
Answer: a) Fluorine (F)
Explanation: While fluorine is expected to have high electron affinity, it is actually lower than chlorine’s. This is due to the small size of fluorine, which causes electron-electron repulsion when an extra electron is added, lowering its electron affinity.
- The ability of an atom in a molecule to attract shared electrons towards itself is called:
a) Ionization energy
b) Electron affinity
c) Electronegativity
d) Metallic character
Answer: c) Electronegativity
Explanation: Electronegativity is a measure of an atom’s ability to attract bonding electrons in a molecule. It differs from ionization energy and electron affinity, which refer to individual atoms in different contexts.
- Which of the following elements shows diagonal relationship with Lithium?
a) Sodium
b) Magnesium
c) Potassium
d) Beryllium
Answer: d) Beryllium
Explanation: Lithium and beryllium show a diagonal relationship due to similarities in their properties such as atomic and ionic sizes, electronegativity, and polarization power, despite being in different groups.
- Which of the following elements has the highest electronegativity?
a) Oxygen (O)
b) Nitrogen (N)
c) Fluorine (F)
d) Chlorine (Cl)
Answer: c) Fluorine (F)
Explanation: Fluorine is the most electronegative element in the periodic table. It has a strong ability to attract electrons towards itself in a chemical bond due to its small size and high effective nuclear charge.
- Which of the following statements is incorrect about the trends in the periodic table?
a) Electronegativity decreases down a group.
b) Atomic radius increases down a group.
c) Ionization energy increases across a period.
d) Metallic character increases across a period.
Answer: d) Metallic character increases across a period
Explanation: Metallic character decreases across a period from left to right due to increasing ionization energy and electronegativity, making elements less likely to lose electrons and form positive ions.
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